Compare limits Bayesian (two diff. prior) and frequentist
on counting experiments with background
No uncertainty on the background.

To calculate the frequentist limit use result $\sum_{n=0}^N \frac{\mu^n e^{-\mu}}{N!} = \frac{1}{N!}\Gamma(N+1, \mu)$

where $\Gamma(a,b) = \int_b^{\infty} t^{a-1}e^{-t} dt$